linux解压.zip文件乱码处理的一个脚本

兼容适配 软件兼容
1

[postbg]bg9.png[/postbg]使用linux系统往往会下载windows平台编码的文件一般是.zip文件/

#!/usr/bin/env python2
# -*- coding: utf-8 -*-

import os
import sys
import zipfile
import argparse

s = '\x1b[%d;%dm%s\x1b[0m'       # terminual color template

def unzip(path):

   file = zipfile.ZipFile(path,"r")
   if args.secret:
   file.setpassword(args.secret)

   for name in file.namelist():
   try:
   utf8name=name.decode('gbk')
   pathname = os.path.dirname(utf8name)
   except:
   utf8name=name
   pathname = os.path.dirname(utf8name)

   #print s % (1, 92, '  >> extracting:'), utf8name
   #pathname = os.path.dirname(utf8name)
   if not os.path.exists(pathname) and pathname != "":
   os.makedirs(pathname)
   data = file.read(name)
   if not os.path.exists(utf8name):
   try:
   fo = open(utf8name, "w")
   fo.write(data)
   fo.close
   except:
   pass
   file.close()

def main(argv):
   ######################################################
   # for argparse
   p = argparse.ArgumentParser(description='解决unzip乱码')
   p.add_argument('xxx', type=str, nargs='*', \
   help='命令对象.')
   p.add_argument('-s', '--secret', action='store', \
   default=None, help='密码')
   global args
   args = p.parse_args(argv[1:])
   xxx = args.xxx

   for path in xxx:
   if path.endswith('.zip'):
   if os.path.exists(path):
   print s % (1, 97, '  ++ unzip:'), path
   unzip(path)
   else:
   print s % (1, 91, '  !! file doesn\'t exist.'), path
   else:
   print s % (1, 91, '  !! file isn\'t a zip file.'), path

if __name__ == '__main__':
   argv = sys.argv
   main(argv)

复制代码可以另命名但后缀是py不要忘记他需要python解析
用法：

python2 unzip.py azipfile1.zip azipfile2.zip
python2 unzip.py azipfile.zip -s secret
# -s 密码
2

不错

3

good!